Question

A driver leaves a city at 6 a.m. and another driver leaves the city from the same place w
11:30 a.m. in the same direction. If the average speed of the first driver was 55 kmh and the
driver was 62 km/h, find the time at which they will be together​

Answer 1

Answer:

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Step-by-step explanation:

Lets assume, they will be together in 't' hours after 6 a.m. when the first driver leaves the city.

As the second driver leaves at 11:30 a.m., that means he leaves (11:30am - 6am)= 5.5 hours after the first driver. So, the time duration for second driver is (t- 5.5) hours.

The average speed of the first driver was 55 km/hour and the second driver 65 km/hour.

As Distance= Speed × Time , so the equation will be ....

$55t = 65(t - 5.5) \\ \\ 55t = 65t - 357.5 \\ \\ 65t - 55t = 357.5 \\ \\ 10t = 357.5 \\ \\ t = \frac{357.5}{10} \\ \\ t = 35.75$

So, they will be together after 35.75 hours or 35 hours 45 minutes from 6 am , which is at (6 am+ 35 hours 45 minutes)= 5:45 p.m. on the next day.