A driver takes 0.02 secs to apply brakes. If he is driving car at a speed of 54kmph and brakes cause a deceleration of 6m/s2. Find the distance travelled by the car, after he sees the need to apply brakes.
Answers
Answered by
6
In the 2 seconds of reaction time, distance traveled = 54km/hr×2secs = 54000m/3600sec × 2 sec = 30 m
apply third law of motion
v^2 - u^2 = 2as
0^2 - 54^2 = 2× -6 × s Final speed is zero on coming to rest.
-2916 = -12s
s = 243 m
Total distance traveled = 30m + 243m = 273mans...
hope this will help...
apply third law of motion
v^2 - u^2 = 2as
0^2 - 54^2 = 2× -6 × s Final speed is zero on coming to rest.
-2916 = -12s
s = 243 m
Total distance traveled = 30m + 243m = 273mans...
hope this will help...
Similar questions