A driver takes 0.2 s to apply brakes. If he is driving at a speed 54km/hr and the brakes cause a deceleration of 6m/s^2 find the distance travelled by the car,after he sees the need to apply brakes
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u=54km/hr=15m/s
v=0m/s
a=(-6m/s^2)
t=0.2sec
s=?
s=ut+1/2at^2
s=15×2/10+1/2×(-6)×2/10
s=3.6m
v=0m/s
a=(-6m/s^2)
t=0.2sec
s=?
s=ut+1/2at^2
s=15×2/10+1/2×(-6)×2/10
s=3.6m
the formula says ut+1/2at^2 you have not put ^2 in 2/10
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