A driver takes0.2seconds to apply the brakes. If he is driving car at a speed of 54km/h and the brakes cause a retardation of 6m/s2,find the distance traveled by the car after he sees the need to put the brakes. plzz give correct answer
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GIVEN:
- T = 0.2s
- Initial velocity, u = 54 km/h = 54 x 5/18 = 15 m/s
- Deceleration, a = 6 m/s^2
- Final velocity, v = 0 m/s
TO FIND:
- Find the distance traveled by the car after he sees the need to put the brakes.
SOLUTION:
Now, Distance travelled by car during reaction time :
Distance = Speed x time
Distance = 15 x 0.2
=3 m
From third equation of motion:
v² - u² = 2as
0² - 15 x 15 = 2 x -6 x s
s = -15 x 15 / -12
s = 225 / 12a
s = 18.75 m
Distance = 18.75 + 3 = 21.75 m
Therefore, the total distance travelled by the driver after he sees the need to put the brakes on is 21.75 m
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