Physics, asked by imma8895, 1 year ago

A drop of some liquid of volume 0.04 cm30.04 cm3 is placed on the surface of a glass slide. Then another glass slide is placed on it in such a way that the liquid forms a thin layer of area 20cm220cm2 between the surfaces of the two slides. To separate the slides a force of 1610516105 dyne has to be applied normal to the surfaces. The surface tension of the liquid is (in dyne-cm1cm1):

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Answered by andthe
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A drop of some liquid of volume 0.04 cm30.04 cm3 is placed on the surface of a glass slide. Then another glass slide is placed on it in such a way that the liquid forms a thin layer of area 20cm220cm2 between the surfaces of the two slides. To separate the slides a force of 1610516105 dyne has to be applied normal to the surfaces. The surface tension of the liquid is (in dyne-cm1cm1):

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