Question

A drop of water of radius 6mm breaks into number of droplets each of radius 1 mm how many droplets will formed​

Answer 1

Answer:

Volume of large water drop

= (4/3)*pi* 6³

Now

This should be equal to n drops of 1 mm radius

Hence

(4/3)*pi* 6³ = n* (4/3)* pi* 1³

n = 216

Hence 216 drops will be formed.

Answer 2

216 droplets will formed.

Explanation:

The volume of big drop is given as

$V=\frac{4}{3}\pi R^3$

Here R is the radius of big drop.

Similarly the volume of small drop,

$v=\frac{4}{3}\pi r^3$

Here r is the radius of small drop.

As the big drop breaks in small droplets, so

Volume of a big drop of radius = n (volume of small drop of radius)

$n=\frac{V}{v}$

Here n is the number of droplets.

Given R =6 mm and r = 1 mm.

Substitute the given values, we get

$n=\frac{\frac{4}{3}\pi\times (6mm)^3 }{\frac{4}{3}\pi\times (1mm)^3}$

n = 216 .

Thus, 216 droplets will formed.

#Learn More: Volume of drop.

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