A drum full of Kerosene weighs 21 hole 2 upon 3 L. If empty drum weighs 11 hole 3 upon 5 L then what is the weight of the kerosene in the drum
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Total weight = weight of drum + weight of wheat
( 80 1/6 = 80 + 1/6 )
(15 3/4 = 15 + 3/4 )
U should convert into simplest form so your calculation speed will increase ...
Put given data in equation
80 + 1/6 = 15 + 3/4 + w
W = (80-15) + ( 1/6 - 3/4 )
W = 65 - 7/12
W = 64 + 1 - 7/12
W = 64 + 5/12
W = 64 5/12 kg
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