Physics, asked by rajneesh8, 1 year ago

a drunkard is walking along a straight road he takes 5 step forward and three step backward followed by 5 step forward and three step backward and his show on each state is 1 m long takes 1 seconds there is a bit on road 11 metre away from starting point the drunkard will fall in the pit

Answers

Answered by jakeer1
2
For 8 total steps it takes 8 seconds,
and moves in total 2 steps forward (2 m)
Therfore,
3*2 m = 6 m
At 3rd cycle Time Elapsed 24 s
After walking 5 m forward, he takes 5 s more.
It becomes 11 m.
Time = 24 + 5 = 29m
Answered by Anonymous
3

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Distance covered with 1 step = 1 m

Time taken = 1 s

Time taken to move first 5 m forward = 5 s

Time taken to move 3 m backward = 3 s

Net distance covered = 5 – 3 = 2 m

Net time taken to cover 2 m = 8 s

Drunkard covers 2 m in 8 s.

Drunkard covered 4 m in 16 s.

Drunkard covered 6 m in 24 s.

Drunkard covered 8 m in 32 s.

In the next 5 s, the drunkard will cover a distance of 5 m and a total distance of 13 m and falls into the pit.

Net time taken by the drunkard to cover 13 m = 32 + 5 = 37 s

I hope, this will help you

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