Question

A drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1m long and takes 1s. There is a pit on the road 11 m away from the starting point. The drunkard will fall into the pit after how many seconds?​

Answer 1

GIVEN:
1 STEP=1M
PIT=11M FAR

SOLN:
5*11=55sec......(1)
3*11=33sec......(2)

subracting eq 2 from 1
we get
=55-33
=22 seconds
we conclude that the drunkard will fall into the pit after 22seconds

Answer 2

Answer:

Explanation:

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