Question

A drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1 m long and takes 1 s. There is a pit on the road 11 m away from the starting point. The drunkard will fall into the pit after:

Answer 1

Answer:

He moves 5 steps forward and 3 steps backward in 8sec after that he is 2m away from an initial position

x= 5-3=2m in 8 sec

after 24sec he will 6m away from an initial position

He moves further 5m forward then he falls in a pit which is 11m away from the initial position.

total time T=24+5=29sec.

Answer 2

Answer:For 8 total steps it takes 8 seconds, and moves in total 2 steps forward (2 m)

Therefore, 3*2 m = 6 m At 3rd cycle

Time Elapsed 24 s

After walking 5 m forward, he takes 5s more. It becomes 11 m.

Time = 24 + 5 = 29m

Explanation: