Question

A drunkard moves in such a way that he takes 5 step gorward 3 steb backward and so on. Each of his steps is 1m long and take 1 sec.Find displacement and distance travelled after 15 sec.

Answer 1

Howdy!!!

your answer is --

Distance covered with 1 step = 1 m

Time taken = 1 s
Time taken to move first 5 m forward = 5 s

Time taken to move 3 m backward = 3 s

Net distance covered = 5 – 3 = 2 m
Net time taken to cover 2 m = 8 s
Drunkard covers 2 m in 8 s.

so, 8 s = 2m

=> 1s = 2/8m

=> 15 s = 2/8×15 m

=>15 s = 3.75 meter

so, in 15 s , distance = 3.75 meter

displacement is also 3.75 meter


hope it help you

Answer 2

Answer:==============ⓢⓦⓘⓖⓨ

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Distance covered with 1 step = 1 m

Time taken = 1 s

Time taken to move first 5 m forward = 5 s

Time taken to move 3 m backward = 3 s

Net distance covered = 5 – 3 = 2 m

Net time taken to cover 2 m = 8 s

Drunkard covers 2 m in 8 s.

Drunkard covered 4 m in 16 s.

Drunkard covered 6 m in 24 s.

Drunkard covered 8 m in 32 s.

In the next 5 s, the drunkard will cover a distance of 5 m and a total distance of 13 m and falls into the pit.

Net time taken by the drunkard to cover 13 m = 32 + 5 = 37 s

I hope, this will he

Explanation: