Science, asked by tilak722mahida, 6 months ago

A drunkard moves on a straight road such that he takes 7 steps forward and 2 steps backward in each cycle. If the stride length of each step is 1 feet and the drunkard moves with a speed 2 feet/s in forward direction and 4 feet/s in backward direction, then the time after which the drunkard will fall into a pit 11 feet further from his starting point is

6 s

2.5 s

7s

2 s

Answers

Answered by jaspreet5780
0

Answer:

I am sorry actually I am not understand ur question

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