Question

A drunkard walking along a narrow lane makes 5steps forward and 3 steps backward and so on .How long he takes to fall in pit 15m away from the starting point.?Each step is 1m long and takes 1s. ​

Answer 1

Answer:

Explanation: A drunkard walking in a narrow lane takes 5 steps forward and 3 steps backward, followed again by 5 steps forward and 3 steps backward, and so on. Each step is 1 m long and requires 1 s. Plot the x-t graph of his motion. Determine graphically and otherwise how long the drunkard takes to fall in a pit 13 m away from the start.

Answer 2

✔️ Answer ✔️

Your answer:-

He moves 5 steps forward and 3 steps backward in 8sec after that he is 2m away from an initial position

x= 5-3=2m in 8 sec

after 24sec he will 6m away from an initial position

He moves further 5m forward then he falls in a pit which is 11m away from the initial position.

total time T=24+5=29sec.

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