Factoring with repeated of the difference of square formula. Factor the answer completely.
3y4 – 3u4y4.
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3y4 – 3u4y4.
= 3y4(1 – u4).
= 3y4(1 – (u2)2).
= 3y4(1 + u2)( 1 - u2) [since we know a2 – b2 = (a + b)(a – b)].
= 3y4(1 + u2)( 1 + u) ( 1 - u).
Answer - 3y4(1 + u2)( 1 + u) ( 1 - u)
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3y4 – 3u4y4.
= 3y4(1 – u4).
= 3y4(1 – (u2)2).
= 3y4(1 + u2)( 1 - u2) [since we know a2 – b2 = (a + b)(a – b)].
= 3y4(1 + u2)( 1 + u) ( 1 - u).
Answer - 3y4(1 + u2)( 1 + u) ( 1 - u)
⤴️_____HOPE HELP YOU_____⤴️
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the identity is a^2-b^2=(a+b)(a-b)
is the answer.....
is the answer.....
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