a dur is rolled e is event that the upper most face show a number multiply of 3 write n(e) and p(e)
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Total no. of outcomes; n(s) = 6 [1, 2, 3, 4, 5, 6]
No. Of favourable outcomes; n(e) = 2 [3, 6]
P(getting a multiple of 3) = n(e)/ n(s)
= 2/6 =1/3
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