Question

A dynamometer is attached to two blocks of masses 6kg and 4kg forces of 20N and 10N are applied on the blocks as shown in figure . Find the dynamometer reading in the steady state

Answer 1

The average force is

(20 + 10) / 2 = 15 N

This means that the reading on the dynamometer lies between 10 and 15.

Let the reading on the dynamometer be x N.

Equating the two we have :

(20 - x) /6 = (x - 10)/4

80 - 4x = 6x - 60

140 = 10x

x = 140/10

x = 14 N

The acceleration = (20 - 14)/6 = 1

= 1 m/s²

Answer 2

For the mass of 6kg – 50 – D = 6a ….... (i) For the mass of 4kg – D – 30 = 4a ….....(ii) Solving (i) and (ii) we get a = 2m/s2 Putting the value of a in (ii) we get D – 30 = 4(2)=8

so D=38 N

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