a dynometer D is attached to two blocks af masses 6kg and 4kg.forces of 20N and 10N are appliied on the blocks as shown in fig. the force F=20Nact on 6kg onleftside &F=20N act on 4kg on right side of the block
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reading of dynometer is given by=(m2F1+m1F2)/m1+m2
so putting these values
reading=4×20+6×10/4+6
=80+60÷10
=140/10=14ans.
so putting these values
reading=4×20+6×10/4+6
=80+60÷10
=140/10=14ans.
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