a
E.
Prove DE || BC
P
C
B
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in traingle ADE and ABC
EA=AC. (Given)
angle EAD =angle BAC. (Vertically Opp. angle)
BA=AD. (Given)
traingle ADE is congruent to traingle ABC (by SAS criteria of congruency)
angle ABC =angle ADE. (CPCT)
since angle ABC equals angle ADE
and they are also alternate angle
= DE//BC (hence proved)
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