Math, asked by divyanshu668692, 10 months ago

deer in the herd.
9. Agrandfather is ten times older than his granddaughter.
He is also 54 years older than her. Find their present ages.
10 Aman's age is three times his son's age Ten vears ago he was five times his son​

Answers

Answered by sunitabaknad1
2

Answer:

Hello friend, here's ur answer.

1) Grandfather's age: - 10x

  Granddaughter's age: - x

10x=x+54

10x-x=54

9x=54

x=54/9

x=6

Grandfather's age = 10x = 10*6 = 60 Years

Granddaughter's age = x = 6 Years

2) Baichung's father's age = x

Baichung's grandfather's age = x+26

Baichung's age = x-29

(x)+(x+26)+(x-29) = 135

3x-3=135

3x=135+3=138

3x=138

x=138/3

x= 46 Years

Baichung's Age: - 46-29 = 17 Years

Baichung's father's age: - 46 Years

Baichung's grandfather's age: - 46+26 = 72 Years

3) Ravi's present age: - x

x+15 = 4x

15=4x-x

15=3x

x=15/3

x= 5 years

4) Son's age= x

Aman's age=3x

5(x-10) = 3x-10

5x-50=3x-10

2x=40

x=20

Son's age=20 Years

Aman's age=60 Years

Hope it helps

Answered by Anonymous
0

Answer:

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Step-by-step explanation:

The grandfather and his granddaughter's present age. Granddaughter's age is 10 times lesser than the grandfather and the grandfather's age is 54 more than his granddaughter. Thus, the present ages of grandfather and his granddaughter are 60 years and 6 years respectively.

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