Physics, asked by itsaparna, 1 year ago

A electric heater rated 800W operates 6h/day. Find the cost of energy to operate it for 30 days at rs 3.00 per unit

Answers

Answered by JunaidMirza
21
Total time it operates for 30 days = 30 × 6 = 180 hours

Energy = Power × Time
= 800 W × 180 hour
= 144000 Wh
= 144 kWh

Cost = 144 kWh × ₹3.00/kWh = ₹432

P.S
You should know the fact we take 1 unit = 1 kWh
So, ₹3.00 per unit means it charges ₹3 for every 1 kWh of energy consumption.
Answered by tanu21533
2

Answer:

Explanation:

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