Question

A electron hole pairs are formed when maximum 6000 Å wavelength of light is incident on the semiconductor.What will be the band gap energy of the semiconductor? [h= 6.62*10⁻³⁴ J S] [Ans: 2.07 eV]

Answer 1

Answer:

the band gap enrgy will be 2.07 eV.

Explanation:

Given,

$\textrm{wavelength of light} = 6000\ A^o$

                                             $=6000\times 10^{-10}\ m$

                                            $= 6\times 10^{-7} m$

$\textrm{planck's constant, h\ }=\ 6.62\times 10^{-34}\ JS$

$\textrm{speed of light, c}= 3\times 10^{8}\ m/s$

$\textrm{Now, band gap energy }= \dfrac{h.c}{\lambda}$

                                        $=\ \dfrac{6.62\times 10^{-34}\times 3\times 10^{8}}{6\times 10^{-7}}$}

                                        $=\ 3.31\times 10^{-19}\ J$

$\textrm{now, energy in eV }= \dfrac{3.31\times 10^{-19}}{1.6\times 10^{-19}}$

                               = 2.07 eV

Hence, the band gap enrgy will be 2.07 eV.