Physics, asked by subedikaruna973, 5 hours ago

A engine of mass 2000 kg develop if it to drive up an incline of 1 in 10 with a speed of 12m/s ?The resistance due to friction is 200N.calculate the applied force . What HP must the on engine?

Answers

Answered by Anonymous

4

Answer:

Downward force F=mgsinθ+frictional force

F=2000×10×

10

1

+200

F=2200N

P=FV=2200×10=22000W=22KW

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