Question

A equilateral triangle is formed with each side having a resistance of 6 Ω. What is the resistance across any side of the triangle

Answer 1

Answer:

4/3 ohms

Explanation:

This seems to be a question of adding resistances.

In series Rt = R1 + R2 + … (for proof use V=IR where I is a constant)

In parallel 1/Rt = 1/R1 + 1/R2 + … (for proof use V=IR where V is a constant)

So - if we draw a diagram we will see that two of the resistors are in series (giving Rt = 4): we now have two resistors in parallel (4 ohms and 2 ohms)

So the total resistance derives from 1/Rt = 1/4 + 1/2 i.e. 1/Rt = 3/4

Therefore the effective resistance is 4/3 ohms.