Question

A erect image 3 times the size of the object is obtained with a concave mirror of radius of curvature 36cm what is position of image

Answer 1

Answer:

v= -3 u actually u is negative. Hence v is positive. R = -36 cm => f = R/2 = -18 cm , negative for a concave mirror. the object is placed 12 cm from pole of concave mirror , less than the focal length, to have an ERECT magnified image 3 times the object.

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