Question

a examinee gather 35% that calculate as 20 less then pass mark and another one gather 45% that calculate as 20 more than pass mark, pass mark ?

Answer 1

$<b>Heya mate. (^_-). Solution below.$
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[] Let the maximum marks be 'x'.



• It is given that an examinee got 35% of total marks and failed by 20 marks.

So, passing marks,

= 35% of x + 20

= 35/100 × x + 20

= 35x/100 + 20... [equation i]


• It is also given that another examinee got 45% of total marks and passed by 20 marks.

So, passing marks,

= 45% of x - 20

= 45/100 × x - 20

= 45x/100 - 20... [equation ii]



[] But, passing marks has to be one.

=>>> 35x/100 + 20 = 45x/100 - 20

=> 20 + 20 = 45x/100 - 35x/100

=> 40 = (45x - 35x)/100

=> 40 = 10x/100

=> 40 × 100/10 = x

=> 4000/10 = x

=> 400 = x

•°• Total marks = x = 400 marks.



[] Now, passing marks,

= 35x/100 + 20

= (35 × 400)/100 + 20

= 14000/100 + 20

= 140 + 20

= 160.


$<marquee>Hence, thepassing marks = 160.</marquee>$
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Thank you.. ;-)