a. Explain Bohr and Burry rules for distribution of electrons into different shells.
b. Write the distribution of electrons in Chlorine atom (Z = 17).
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(a) Bohr-Bury Rules :
(i) The maximum no. of electrons present in a shell is given by the formula 2n^2 (where n is shell no.).
(ii) The maximum no. of electrons that can be accommodated in the outermost orbit is 8.
The distribution of electrons in different orbits or shells is governed by a scheme known as Bohr buryscheme.The arrangement of electrons in various energy levels of an atom is known as the electronic configuration of the atom.
(i) The maximum no. of electrons present in a shell is given by the formula 2n^2 (where n is shell no.).
(ii) The maximum no. of electrons that can be accommodated in the outermost orbit is 8.
The distribution of electrons in different orbits or shells is governed by a scheme known as Bohr buryscheme.The arrangement of electrons in various energy levels of an atom is known as the electronic configuration of the atom.
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(a) Bohr and Bury Scheme - Important Rules
=>Maximum number of electrons that can be accommodated in a shell is given by 2n2 where n = shell number.
=>For 1st energy level, n = 1 Maximum number of electrons in 1st energy level = 2n2= 2 x (1)^2 = 2.
=>For 2nd energy level n = 2Maximum number of electrons in the 2nd energy level = 2n22 x 22 = 2 x 4 = 8.
=>For 3rd energy level n = 3Maximum number of electrons in the 3rd energy level = 2n2= 2x(3) 2= 2 x 9 = 18.
=>For 4th energy level n = 4Maximum number of electrons in the 4th energy level = 2n2= 2x(4) 2= 2x16 = 32.
=>The outermost shell of an atom cannot accommodate more than 8 electrons, even if it has a capacity to accommodate more electrons. This is a very important rule and is also called the Octet rule. The presence of 8 electrons in the outermost shell makes the atom very stable.
(b) ELECTRONIC DISTRIBUTION IN CHLORINE
(2,8,7)
=>Maximum number of electrons that can be accommodated in a shell is given by 2n2 where n = shell number.
=>For 1st energy level, n = 1 Maximum number of electrons in 1st energy level = 2n2= 2 x (1)^2 = 2.
=>For 2nd energy level n = 2Maximum number of electrons in the 2nd energy level = 2n22 x 22 = 2 x 4 = 8.
=>For 3rd energy level n = 3Maximum number of electrons in the 3rd energy level = 2n2= 2x(3) 2= 2 x 9 = 18.
=>For 4th energy level n = 4Maximum number of electrons in the 4th energy level = 2n2= 2x(4) 2= 2x16 = 32.
=>The outermost shell of an atom cannot accommodate more than 8 electrons, even if it has a capacity to accommodate more electrons. This is a very important rule and is also called the Octet rule. The presence of 8 electrons in the outermost shell makes the atom very stable.
(b) ELECTRONIC DISTRIBUTION IN CHLORINE
(2,8,7)
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