Question

A factory is to pack pencils in boxes of 8 and 10 pieces. What is the smallest number of pencils that can packed using the boxes
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Answer 1

Given,

Box capacity = 8 and 10 pieces per box.

To find,

The smallest number of pencils that can be packed by using both kind of boxes.

Solution,

We can simply solve this mathematical problem by using the following mathematical process.

First of all we need to calculate the prime factors of the given capacities.

8 = 2×2×2

10 = 5×2

Minimum amount of pencils that can be packed by using both kind of boxes at the same time, is :

= Factors of capacity of first box × Factors of capacity of second box

= 2×2×2×5×2

= 80

Verification :

For 80 pencils we need 5 boxes of capacity 8 pieces per box and 4 boxes of capacity 10 pieces per box. (8×5+10×4 = 80)

Hence, 80 pencils is the minimum amount that can be packed using both kind of boxes.

Answer 2

Answer:

Step-by-step explanation: