Question

A factory manufactures 120000 pencils daily the pencils are cylindrical in shape each of length 25 cm and circumference of base is 1.5 CM determine the cost of colouring the curved surface of pencil manufactured in one day at rupees 0.05 per DM square

Answer 1

A)

 

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Toolbox:Equation of line whose join of points is (x1,y1)(x1,y1) and (x2,y2)(x2,y2)is y−y1y2−y1y−y1y2−y1=x−x1x2−x1=x−x1x2−x1

Step 1 :

The equation of the square formed by the lines are x=0,y=0,x=1andy=1x=0,y=0,x=1andy=1respectively.



Hence the vertices of the square are 0(0,0),A(1,0),B(1,1),C(0,1)0(0,0),A(1,0),B(1,1),C(0,1)respectively

Hence the equation of the diagonals 0B is

y−y1y2−y1y−y1y2−y1=x−x1x2−x1=x−x1x2−x1

(i.e) y−01−0y−01−0=x−01−0=x−01−0

⇒y=x⇒y=x--------(1)

equation of the diagonal AC is

y−01−0y−01−0=x−10−1=x−10−1

⇒−y=x−1⇒−y=x−1

⇒x+y=1⇒x+y=1

Hence 'A' is the correct answer.

Answer 2

Answer:

Rs 2250

Explanation:

  CSA = 2*pie*r*h

  circumference[2*pie*r]= 1.5 cm

   height =25 cm

  C S A= 1.5 * 25

             =37.5 cm[squared]  

total csa=37.5*120000

             =45000000

1 cm [square] =1/1000 m[square]

   total   cost  =45000*0.05

              =Rs 2250