A fair die is tossed eight times. what is the probability of exactly two 3's, three 1's, and three 6's?
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A fair die is tossed eight times.
the probability of exactly two 3's is 2×1/ 6^8 = 1/3^8×2^7
the probability of exactly Three 1s 3×1/3^7×2^8
and the probability of exactly three 6's is 3×1/6^8 = 1/3^7×2^8
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A fair die is tossed eight times.
the probability of exactly two 3's is 2×1/ 6^8 = 1/3^8×2^7
the probability of exactly Three 1s 3×1/3^7×2^8
and the probability of exactly three 6's is 3×1/6^8 = 1/3^7×2^8
pls mark as a brainlist
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