Please help Q. 8 and 9. Please show how to solve
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ques 8.
Given a + b + c = 0
⇒ a3 + b3 + c3 = 3abc → (1)
Consider, (a2/bc) + (b2/ca) + (c2/ab)
= (a3 + b3 + c3)/abc
= 3abc/abc = 3 ,D is ans
ques 9
a^1/3+b^1/3+c^1/3=0
(a^1/3+b^1/3)^3=(-c^1/3)^3
a+b+3a^1/3×b^1/3(a^1/3+b^1/3)=-c
a+b+c+3a^1/3×b^1/3(-c^1/3)=0
a+b+c=3a^1/3b^1/3c^1/3
(a+b+c)^3=27abc..B is the ans
Given a + b + c = 0
⇒ a3 + b3 + c3 = 3abc → (1)
Consider, (a2/bc) + (b2/ca) + (c2/ab)
= (a3 + b3 + c3)/abc
= 3abc/abc = 3 ,D is ans
ques 9
a^1/3+b^1/3+c^1/3=0
(a^1/3+b^1/3)^3=(-c^1/3)^3
a+b+3a^1/3×b^1/3(a^1/3+b^1/3)=-c
a+b+c+3a^1/3×b^1/3(-c^1/3)=0
a+b+c=3a^1/3b^1/3c^1/3
(a+b+c)^3=27abc..B is the ans
AdarshDivyanshu:
pls mark it as brainly
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