Question

a fair die is tossed twice find the probability of getting 4,5 or 6 on the first toss and 1,2,3 or 4 on the second toss​

Answer 1

Answer:

hey mate

Step-by-step explanation:

When a dice is tossed , total possible outcome = {1,2,3,4,5,6}

When , Dice is tossed twice Total Possible Outcome = 6²=36

Favorable Outcome = A={4,5,6} and B={1,2,3,4}

Probability of an event =

P(A)=

P(B)=  

Probability of getting a 4,5,6 on the first toss and a 1,2,3,4 on the second toss

     = P(A) × P(B)

        =                    

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