Math, asked by DDom, 10 months ago

J e r k (denoted by JJJ) can be defined as a function of acceleration (denoted by aaa) and time (denoted by ttt) using this formula:
J=\dfrac{a}{t}J=
t
a

J, equals, start fraction, a, divided by, t, end fraction
Acceleration is measured in \dfrac{\text{m}}{\text{s}^2}
s
2

m

start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction, and time is measured in \text{s}sstart text, s, end text.
Select an appropriate measurement unit for j e r k
Choose 1 answer:

Answers

Answered by muscardinus
0

Given that,

J e r k can be given by, J=\dfrac{a}{t}, a is acceleration and t is time.

To find,

Measurement unit for J e r k.

Solution,

The rate of change of acceleration is called j e r k. If a is acceleration and t is time. It can be given by :

J=\dfrac{a}{t}

The SI unit of acceleration is m/s^2 and for time it is s.

So,

J=\dfrac{m/s^2}{s}\\\\J=m/s^3

So, the measurement unit for J e r k is m/s^3.

Answered by MrSmart12345
0

Answer:

J = acceleration/time

Step-by-step explanation:

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