Question

a fair for is rolled twice find the probability of getting 4 in the first roll and getting any other number then 4 in the second throw ​

Answer 1

Answer:

The die roll is sequential and done without replacements, so the calculation is fairly simple; assuming a six-sided die:

P(A): First roll, showing 4: 16

P(B): Second roll, showing an odd number: 12

The probability for our question is received by simply multiplying the two

P(A)P(B)=(16)(12)=112≈0.0833...

So our desired probability is approximately 8.3%.

hope it's help you ✌️✌️

Answer 2

P(4 on 1st roll or odd on 2nd roll)= 1-[P(not 4 on 1st roll and not odd on 2nd roll)]

= 1-(5/6 x 1/2)

= 1-5/12

= 7/12

7/12 is the probability of at least one of the two events occurring.