Question

a falcon is diving at a speed of 30m/s .it accelerates at a rate of 40m/s^2 and reaches a speed of 100m/s.calculate the distance it travels during its acceleration​

Answer 1

Answer:

Explanation:

Solution,

Here, we have

Initial velocity, u = 30 m/s

Final velocity, v = 100 m/s

Acceleration, a = 40 m/s²

To Find,

Distance traveled, s = ?

According to the 3rd equation of motion,

We know that,

v² - u² = 2as

So, putting all the values, we get

⇒ v² - u² = 2as

⇒ (100)² - (30)² = 2 × 40 × s

⇒ 10000 - 900 = 80s

⇒ 9100 = 80s

⇒ 9100/80 = s

⇒ s = 113.75 m.

Hence, the distance traveled by falcon is 113.75 m.

Answer 2

Given:-

• Initial velocity (u) =30m/s
• Final velocity (v) =100m/s
• Acceleration (a) =40m/s²

To Find:-

⋄ Distance travelled by Falcon (s).

Solution :-

By using 3rd equation of motion

$v {}^{2} = u {}^{2} + 2as \\ \\ 100 {}^{2} = 30 {}^{2} + 2 + 40 \times s \\ \\ 10000 = 900 + 80 \times s \\ \\ 10000 - 900 = 80 \times s \\ \\ s = \frac{9100}{80} \\ \\ s = 113.75m$

∴The distance covered by Falcon is 113.75m