Math, asked by sanjeevrawat4710, 11 months ago

A family has husband, wife and three
children A, B and C. The present age of
the husband is 5 years more than the
wife's present age. The wife's present
age is twice the present age of A. The
present age of A is 12 years more than
the present age of B. B's present age is
1(%) times the present age of C. If C is 12
years old at present, what is the present
age of the husband's friend Ram who is
15 years younger than the husband (him)​

Answers

Answered by Anonymous
5

Answer:

According to given data

age of

C=12

B=12×1=12

A=12+12=24

WIFE=24×2=48

HUSBAND =48+5=52

RAM=52_15=37

Answered by shindedropadi
3

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