Physics, asked by kakkar590, 5 months ago

A fan of moment of inertia 0.6kg/m2 is to run up to a working speed of 0.5 rps. find the value of angular momentum of fan (in kgm2/s) ​

Answers

Answered by parul9984
2

Explanation:

Angular momentum=Iω=0.6×0.5×2π=0.6πkg

sec

metre

2

Answered by BrainlyTwinklingstar
8

Given :

Moment of inertia, I = 0.6 kg/m²

Angular velocity, ω = 0.5 rps

To Find :

Angular momentum of a fan.

Solution :

If the body is rotating about a fixed axis, we can write angular momentum of the body

  • L = Iω

Here,

  • L denotes Angular momentum
  • I denotes Moment of inertia
  • ω denotes Angular velocity

by substituting all the given values in the formula,

L = Iω

➝ L = 0.6 × 0.5 × 2π

➝ L = 0.3 × 2π

➝ L = 0.6 π kg.m²/s{.}

thus, Angular momentum of a fan is 0.6π kg.m²/s

Similar questions