A fan of power 50 W is used 8 hours per day and a TV of power 40 W is used 6 hours per day. What is the energy consumption of a fan and TV per month of 30 days?
Answers
Answer:
≈107.64J
Explanation:
1 juole = Watts per second
50W ÷ (8×3600)s
this is to get the energy used by the fan per day which is ≈ 1.736111J
40W ÷ (6×3600)s
this is to get the energy used by the light in one day which is ≈ 1.851852J
total energy per day:
1.736111 + 1.851852 =
to find what is used in a month is:
30 × 3.587963 = 107.63889
≈ 107.64J (to 2d.p.)
Given:
Power rating of fan = 50 W
Usage of fan = 8 hr/day
Power rating of TV = 40 W
Usage of TV = 6 hr/day
To Find:
The energy consumption of a fan and TV per month.
Calculation:
- The energy consumption of fan per day = Power × Time
⇒ Energy consumption of fan per day = 50 × 8 = 400 Wh
- The energy consumption of TV per day = Power × Time
⇒ Energy consumption of TV per day = 40 × 6 = 240 Wh
- Energy consumption of both fan and TV per day = 400 + 240 = 640 Wh
- Energy consumption per month = Energy consumed per day × 30
⇒ E = 640 × 30 = 19200 Wh