a farher is 20 years older than his son. 12 years ago, the age of the father was six times that of his son. find their preset ages.
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12 years ago let's take the son's age as x and his father's age as 6x (6 times).
6x = x+20
6x-x = 20
5x = 20
x=20÷5 =4
so 12 years ago the son's age was 4 and his father's age was 6 times his age . so 6×4=24
Their present ages are= son's age= 4+12=16
father's age=24+12=36
6x = x+20
6x-x = 20
5x = 20
x=20÷5 =4
so 12 years ago the son's age was 4 and his father's age was 6 times his age . so 6×4=24
Their present ages are= son's age= 4+12=16
father's age=24+12=36
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