Math, asked by skenterprises0722, 9 months ago

a farm house having 400 cows have provision of food for 200 days how many cows must be sold after 40 days so that the remaining food last for 200 days more for the remaining cows​

Answers

Answered by shaktivelcleanway
0

Answer:

on, 10 more animals were added. Therefore the number of days required to feed 30 animals: 20 * 6 = (20 + 10) * x 120 = ...

Step-by-step explanation:

on, 10 more animals were added. Therefore the number of days required to feed 30 animals: 20 * 6 = (20 + 10) * x 120 = ...

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