Question

A farmer bought a buffalo for ₹ 44000 and a cow for ₹ 18000. He sold the buffalo at a loss of 15% but made a profit of 10% on the cow. Find his total profit or loss.

Answer 1

Step-by-step explanation:

Cost price of buffalo =Rs.44000

Loss of 5%

∴Loss=

100

5

×44000=2200

Selling price of buffalo =Rs.44000−2200=Rs. 41800

Cost price of cow =Rs.18000

Profit of 10%

Hence,

profit=

100

10

×18000=1800

So, Price=18000+1800=Rs. 19800

Cost price of both cow and buffalo

=44000+18000=Rs. 62000

Selling price of both cow and buffalo

⇒Rs.(19800+41800)=Rs.61600

∴Loss=62000−61600=Rs.400

See answer it may help you

Answer 2

GIVEN :

• Cost price of a buffalo = ₹ 44,000
• Cost price of a cow = ₹ 18,000
• Loss = 5 %
• Profit on a cow = 10 %

TO FIND :

• The total profit and loss = ?

SOLUTION :

Convert the loss percent in rupees,

$\implies \sf \dfrac {5}{100} \times 44000$

$\qquad \large \blue {\underline {\boxed {\sf Loss \ = \ ₹ \ 2200}}}$

Now,

The selling price of a buffalo = ?

$\implies \sf ₹ 44000 \ - \ 2200$

$\therefore$ Selling price of buffalo is ₹ 41800.

Given that, Cost price of a cow = ₹ 18,000 on the profit of 10 %.

So, profit = ?

$\implies \sf Profit \ = \ \dfrac {10}{100} \times 18000$

$\implies \sf Profit \ = \ 1800 \ + \ 800$

$\qquad \large \pink {\underline {\boxed {\sf Profit \ = \ ₹ \ 19800}}}$

Now,

The total price of cow and buffalo = ?

$\implies \sf 44000 \ + \ 18000$

$\implies \sf ₹ 62000$

$\therefore$ The total price of both cow and buffalo is ₹ 62000.

The selling price of the cow and buffalo together,

$\implies \sf ₹ 19800 \ + \ 41800$

$\implies \sf ₹ 61600$

Here, the loss = ?

$\implies \sf Loss \ = \ 62000 \ - \ 61600$

$\qquad \large \red {\underline {\boxed {\sf Loss \ = \ ₹ \ 400}}}$