A farmer bought two buffaloes for rupees 25000 each. After one year he sold one at a loss of 12% and one at a profit of 20% find the SP of each buffaloes and total loss of profit%.
Answers
buffalo = Rs 20000
The milkman made a gain of 5% while selling one buffalo.
This means if C.P. is Rs 100, then S.P. is Rs 105.
C.P. of one buffalo =2000×100/105= Rs 19,047.62
Also, the second buffalo was sold at a loss of 10%.
This means if C.P. is Rs 100, then S.P. is Rs 90.
∴C.P. of other buffalo =2000×100/90= Rs 22222.22
Total C.P. = Rs 19047.62 + Rs 22222.22 = Rs 41269.84
Total S.P. = Rs 20000 + Rs 20000 = Rs 40000
Loss = Rs 41269.84 − Rs 40000 = Rs1269.84
Ans,- ,the loss of milkman is, Rs 1,269.84.
Answer:
buffalo = Rs 20000
The milkman made a gain of 5% while selling one buffalo.
This means if C.P. is Rs 100, then S.P. is Rs 105.
C.P. of one buffalo =2000×100/105= Rs 19,047.62
Also, the second buffalo was sold at a loss of 10%.
This means if C.P. is Rs 100, then S.P. is Rs 90.
∴C.P. of other buffalo =2000×100/90= Rs 22222.22
Total C.P. = Rs 19047.62 + Rs 22222.22 = Rs 41269.84
Total S.P. = Rs 20000 + Rs 20000 = Rs 40000
Loss = Rs 41269.84 − Rs 40000 = Rs1269.84
Ans,- ,the loss of milkman is, Rs 1,269.84.