a farmer buys a tractor for ₹ 70000 and after using it for some time he sell it at a loss of 5% to another former. He also sells it after an year to the third farmer at a loss of 10% . find the price paid by the third farmer. brainly.com
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HEY DEAR ...
5% of 70000=70000*5/100=3500
So first selling price =70000-3500=66500
10% of 66500 = 66500*10/100=6650
So , second selling price = 66500-6650=Rs. 59850
HOPE , IT HELPS ...
5% of 70000=70000*5/100=3500
So first selling price =70000-3500=66500
10% of 66500 = 66500*10/100=6650
So , second selling price = 66500-6650=Rs. 59850
HOPE , IT HELPS ...
Answered by
4
Cost price of the tractor=Rs70000
Loss=5percent
SP=1-l/100of CP
SP=1-5/100of 70000
SP=95/100*70000
=Rs66500
Now,the 2nd farmer sells it at a loss of 10percent.
SP=1-l/100of 66500
SP=1-10/100 of 66500
SP=90/100*66500
=59850
So, the third farmer has to pay Rs59850 for the tractor.
Loss=5percent
SP=1-l/100of CP
SP=1-5/100of 70000
SP=95/100*70000
=Rs66500
Now,the 2nd farmer sells it at a loss of 10percent.
SP=1-l/100of 66500
SP=1-10/100 of 66500
SP=90/100*66500
=59850
So, the third farmer has to pay Rs59850 for the tractor.
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