A farmer connects a pipe of internal diameter 20 cm from a canal into a cylindrical tank which is 10 m in diameter and 2 m deep. If the water flows through the pipe at the rate of 4 km per hour, in how much time will the tank be filled completely?
Answers
Diameter of pipe = 20cm.
Diameter of tank = 10m
Height of tank = 2m.
time taken to fill the tank.
The further Answer is given in the attachment .
Answer :
Diameter of cylindrical tank = 10 m
.°. Radius = 5 m
We know that,
Volume of cylinder = π r^2 h
Volume of cylindrical tank
= 22/7 × 5 × 5 × 2
= 1100/7 m^3
Now,
Radius of pipe = 10 cm = 0.1 m
Water flows at => 4 km/hrs = 4000 m/hrs
Now,
Let's assume the length of water column as 'x' metres
We can say that ,
Volume of the water column = 1100/7 m^3
1100/7 = π r^2 h
1100/7 = 22/7 × 0.1 × 0.1 × 'x'
1100/7 = 0.22x/7
Cancelling 7 on both sides,
1100 = 0.22x
5000 = x
Length of water column = 5000 m or 5 km.
Now,
We have to find the time required for the tank to get filled completely.
Time = Distance/Speed
Time = 5 km /(4 km/hrs)
Time = 1.25 hrs
= 1 hrs 15 mins or 75 mins.
Hence, In 75 mins, the tank be filled completely.
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