Question

please tell the answer ​

Answer 1

give to Tamil I will tell the answer

Answer 2

In Hg[Co(SCN)4] complex, Cobalt is present as Co+2 which has 3d7, it means it has 3 unpaired electrons.

Magnetic moment μ = where, n = number of unpaired electrons

n = 3 for Co+2

μ =

$\sqrt{3(3 + 2)}$

= √15

Option C):√15

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