Math, asked by Parva9300, 8 months ago

A farmer connects a pipe of internal diametre 20 cm from a canal into a cylindrical tank which is 10 m in diameter

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Answered by Anonymous
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Answered by TheCommander
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Correct question →

A farmer connects a pipe of internal diameter of 20 cm from a canal into a cylindrical tank which is 10 m in diameter and 2 m deep .If water flows through the pipe at the rate of 4 km /hr ,In how much time will tank be filled completely ?

Solution →

Water flows at the rate of 4km /hr in pipe

--→ Water flows 4000m in 1hr in pipe of diameter 20cm

\tt VOLUME_{cylindrical\:pipe} = \pi r^2 h  \\\tt VOLUME_{cylindrical\:pipe} = \pi \dfrac{10}{100}  4000 m^3 \\\\\tt VOLUME_{cylindrical\:pipe} = \pi 40m\: -(1)

Now, Diameter of cylindrical tank = 10m

Radius of cylindrical tank = 5m

Height of cylindrical tank= 2m

\tt VOLUME_{cylindrical\:tank} = \pi r^2 h  \\\tt VOLUME_{cylindrical\:pipe} = \pi 5\times5\times2 \\\tt VOLUME_{cylindrical\:pipe} = \pi 50 m^3-(2)

\bigstar \sf Time \:taken\:to \:fill \:tank = \dfrac{ VOLUME_{cylindrical\:pipe} }{VOLUME_{cylindrical\:pipe} }

\bigstar \sf Time \:taken\:to \:fill \:tank = \dfrac{50\pi }{40 \pi }

Total time taken= 5/4hrs or 1  hr 15 minutes.

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