Question

A farmer divided his property between his four sons.he gave half of his property to his eldest son,1/4 of his property to his second son, 1/8 of his property to his third son ,and the remaining of his property was given to the youngest son. a. what fraction of his property was given to the youngest son? b. if the farmer had 32 acres of land as his whole property,how many acres of land did the youngest son get?

Answer 1

HI FRIEND..........

The total fraction of land given to youngest son = 1 - 1/2 - 1/4 - 1/8 = 8 - 4 - 2 - 1 /8 = 1/8.

So total area given to him = 1/8 × 32 = 4 acres of land.

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Answer 2

a). The fraction of the farmer's property that was given to the youngest son = 1/8 .

b). The youngest son got 4 acres of land .

• The fraction of the farmer's property given to the youngest son

        = ( 1 - 1/2 - 1/4 - 1/8 ) = 1/8

• If the farmer had 32 acres of land then the acres of land the youngest son got = ( 1 / 8 ) * 32

                     = 4 acres