Math, asked by GracyGupta, 1 year ago

A farmer divided his square-shaped land into three parts,as shown. He gave two parts to mukesh and the third part to naresh. How much land did each get

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Answered by WARGOD
28

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Answered by GulabLachman
10

Naresh received 11250m² of land and total area received by Mukesh is 11250m².

First, we find the area of the square shaped land.

For that we need to find the value of each side of the square.

Value of side of the square land = (80+70)m = 150m.

Lets calculate first, the area of the land received by Naresh.

If we look closely, we observe the shape of the figure is of a triangle and if that triangle is divided equally, it becomes two right angled triangle having the same base and height.

Height of the right angled triangle (h) = 150m (equal to side of the square)

Base of the right angled triangle (b) = 150/2 = 75m (equal to half the side of the square)

And we know, area of a right angled triangle of height 'h' and base 'b' is represented as:

(1/2) × h × b

And for 2 such right angled triangle of same height and base, area is:

2 × (1/2) × h × b = (h × b)

Now, putting the value of 'h' as 150m and 'b' as 75m, we get Area as:

(150 × 75)m² = 11250m².

Naresh received 11250m² of land.

Now lets calculate, the area of the land received by Mukesh.

We can see that Mukesh has received two portions of land and both are right angled triangle.

For the first right angled triangle,

Base = 80m, Height = 150m

So, area of the first right angled triangle = (1/2) × 150 × 80 = 6000m².

For the second right angled triangle,

Base = 70m , Height = 150m

So, area of the second right angled triangle = (1/2) × 150 × 70 = 5250m².

Thus total area = Area of first right angled triangle + Area of the second right angled triangle = (6000+5250)m² = 11250m².

Thus total area received by Mukesh is 11250m².

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