Question

A farmer has enough food to feed 20 animals in 6 days how long it would there were then animals for his cattle if 10 are more​

Answer 1

Answer:

4 days

Step-by-step explanation:

Given,

A farmer has enough food to feed 20 animals in 6 days

20*6

how long it would there were then animals for his cattle if 10 are more​

if 10 cattle more now cattle are 20+10=30

let x be days

20*6=30*x

x=4 days

Answer 2

Answer:

4 days

Step-By-Step Explanation:

If the number of animals increases, then it will take fewer days to last.

Then the two quantities are in inverse proportions.

Let the required number of days be p.

$\because x_1y_1 = x_2y_2$

Where,

$x_1 = 20, \: y_1 = 6, \: x_2 = 30$ and $y_2 = p$ (let)

=> 20 × 6 = 30 × p

=> 120 = 30p

=> p = 120/30

=> p = 4

Hence the required number of days = 4.