A farmer has enough food to feed 20 animals in 6 days how long it would there were then animals for his cattle if 10 are more
Answers
Answered by
2
Answer:
4 days
Step-by-step explanation:
Given,
A farmer has enough food to feed 20 animals in 6 days
20*6
how long it would there were then animals for his cattle if 10 are more
if 10 cattle more now cattle are 20+10=30
let x be days
20*6=30*x
x=4 days
Answered by
1
Answer:
4 days
Step-By-Step Explanation:
If the number of animals increases, then it will take fewer days to last.
Then the two quantities are in inverse proportions.
Let the required number of days be p.
Where,
and (let)
=> 20 × 6 = 30 × p
=> 120 = 30p
=> p = 120/30
=> p = 4
Hence the required number of days = 4.
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