Question

A farmer has enough food to feed 20 animals in his cattle for 6 days, How long the food last if there where 25more animals in his cattle​

Answer 1

Answer:

Hence, the food will now last for 4 days.

Step-by-step explanation:

here it is your answer

Let the food will now last for x days. Then,  

Number of animals  20            30

Number of days               6            x

Clearly, more is the number of animals, less will be the number of days for food to last.  

So, it is a case inverse proportion.

∴ 20 × 6 = 30x ⇒ x = $\frac{20 X 6}{30}$ = 40

Hence, the food will now last for 4 days.

Answer 2

Answer:

2 days (approx.)

Step-By-Step Explanation:

If the number of animals increases, then it will take fewer days to last.

Then the two quantities are in inverse proportions.

Let the required number of days be p.

$\because x_1y_1 = x_2y_2$

Where,

$x_1 = 20, \: y_1 = 6, \: x_2 = 45$ and $y_2 = p$ (let)

=> 20 × 6 = 45 × p

=> 120 = 45p

=> p = 120/45

=> p = 2.666667

Hence the required number of days = 2.