Question

A farmer has enough food to feed 20 animals in his cattle for 6 days. How long would the food last if there were 10 more animals in his cattle? For more number of animals, the food will last less number of days.​

Answer 1

Answer:

Hence, the food will now last for 4 days.

Step-by-step explanation:

Let the food will now last for x days. Then,  

Number of animals  20       x      30

Number of days                  6                x

Clearly, more is the number of animals, less will be the number of days for food to last.  

So, it is a case inverse proportion.

∴ 20 × 6 = 30x ⇒ x =  

30

20×6

​  

 = 4  

Hence, the food will now last for 4 days.

Answer 2

Step-by-step explanation:

No. of animals a farmer has =20

No. of days food lasts =6

If 10 more animals are added=20+10

=30

No. of days food lasts for 30 animals=x

so,20×6=30x

x=(20×6)÷30

=4days